Question

If E and Fare points on the sides PQ and PR respectively of a APQR. And for each case
EF||QR
PE 3.9 cm, EQ= 3 cm, PF=_ cm and FR =2.4 cm.

Answer 1

The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.

It is given that PE=3.9 cm, EQ=3 cm, PF=3.6 cm and FR=2.4 cm.

Using the basic proportionality theorem, we have

EQ

PE

=

3

3.9

=1.3

FR

PF

=

2.4

3.6

=1.5

Since

EQ

PE



=

FR

PF

Hence, EF is not parallel to QR.