Question

If E, F , G and Hnare the midpoints of the sides AB , BC, CD and AD respt of the parallelogram ABCD..

Then show that,

at(EFGH) = 1\2 at(ABCD)..

Answer 1

Heyy Buddy ❤

Here's your Answer..

Answer 2

$\huge\mathfrak\pink{anSwEr}$

step 1 :- join AC and HF

now in ΔABC

E and F are the mid points

EC //AC

which shows EC = 1/2 AC

//ly in Δ ACD

MG // AC

which shows MG = 1/2 AC

from the above 2 results we can conclude that HGFE is a parallelogram

in //gm ABHF

ΔEFH is on the same base and between same // lines

ΔEFH = 1/2 //gm ABHF

//ly

ΔGFH = 1/2 //gm DHFC

adding both results

we came to know

//gm EFGH = 1/2 //gm ABCD

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