Question

If E,F,G,H are respectively the midpoints of the sides of a parallelogram ABCD,show that

ar(EFGH)=half of ar(ABCD)​

Answer 1

Answer:

==> ar( ∆ EFH ) + ar( ∆ FGH) = ½ ar( ||gm ABFH ) + ½ ar( ||gm DCFH ) . ==> ar( ∆ EFH ) + ar( ∆ FGH) = ½ [ ar( ||gm ABFH ) + ar( ||gm DCFH ) ]

Answer 2

Answer:

it is easy

mark it as brainliest answer

Step-by-step explanation:

•draw a diagonal which cuts the constructed EFGH and bigger parallelogram into two equal parts

•mid point theoram also says that the area of one part of triangle is equal to half of that triangle

so observing that we conclude that area of ABCD=2area(EFGH)