Question

If E,F,GandH are respectively the mid point of the side of a parallelogram ABCD,show that are(EFGH)=1/2ae(ABCD)​

Answer 1

Answer:

,

Step-by-step explanation:

adding (1) and(2)

area(hgf)+area(hef)=1/2 area(dhfc)+1/2 area(hfab)

area(hefg)=1/2[area(dhfc)+area(hfab)]

area(efgh)=1/2area(abcd)

hence proved