If E° for the reaction Fe3+(aq) + e– → Fe2+(aq) is + 0.77 V, what will be E° value for the reaction 2Fe3+(aq) + 2e– → 2Fe2+(aq)?
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Answer:
1.21
Explanation:
2Fe3+ + Fe → 3Fe2+
Fe will react with Fe3+, and gets oxidised & Fe3+gets reduced
Hence,
E=E0 (Fe3+) - E0 (Fe)
= 0.77 - (-0.44)
= 1.21
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