If E1 is the electric field near an infinite charged sheet and E2 is the electric field between two oppositely charged plates then which statement is correct?
options
A. E1=E2
B. E1=E2÷2
C. E1=2E2
D. NONE OF THESE
Answers
As-salamu-alaykum!
Based on Gauss law : We know that Electric field due to an Infinite charged sheet is given by E₁ = σ/2ε₀
where σ is the Surface charge density of the sheet.
Let us move on to the part of Electric field between two oppositely charged plates.
As each charged plate has an Area, The Plate can be considered as a sheet of charges and It is said that they are oppositely charged, that is one is a positively charged plate and the other is negatively charged plate.
⇒ Electric field due to Positively charged Plate is given by E₂ (+) = σ/2ε₀
⇒ Electric field due to Negatively charged Plate is given by E₂ (-) = σ/2ε₀
As the plates are oppositely charged (attractive), the electric field is directed from the positive plate to negative plate.
⇒ The Total Electric field between the two plates is the sum of Electric field of Positive plate and Electric field of Negative plate.
⇒ Total Electric field = E₂ = E₂ (Positive) + E₂ (Negative)
⇒ E₂ = σ/2ε₀ + σ/2ε₀ = σ/ε₀
⇒ The Electric Field between the Oppositely charged plates : E₂ = σ/ε₀
Now consider : E₁ = σ/2ε₀ and E₂ = σ/ε₀
We can clearly notice that E₁ = E₂/2
So Option B is the Correct Answer