If each dimension (edge) of a cube is double than it's volume is how many times of the original volume
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Surface area of a cube is 6a^2
If the edge of a cube is doubled then new surface area= 6×4×a×a
=24a^2
Now, surface area of cube 1÷ Surface area of cube 2 =
24a^2÷6a^2
Therefore, surfacearea is increased by 4 times.
Volume of new cube =2a^3
=8a^3
Therefore, the volume will be increased by 8 times.
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