Question

if each edge of a cube is increased by 10% what will be the percentage of increase in total surface area
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Answer 1

Answer:

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Answer 2

Answer:

LET THE EDGE OF THE CUBE = a

so the tsa of cube would be  ⇒ 6a²

WHEN EDGE OF CUBE IS INCREASED BY 10% ⇒ $\frac{10}{100} * a$ ⇒ $\frac{a}{10}$ (increase by)

                         ⇒ a + $\frac{a}{10}$  ⇒ $\frac{10a + a}{10}$  ⇒ $\frac{11a}{10}$  (is edge when increased)

TSA OF CUBE  ⇒ 6 × $(\frac{11a}{10}) ^{2}$  ⇒ $\frac{726a^{2} }{100}$

increase in tsa of cube ⇒ $\frac{726a^{2} }{100} - 6a^{2}$ ⇒ $\frac{726a^{2} - 600a^{2}}{100}$ ⇒ $\frac{126a^{2} }{100}$

now just convert into %

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