If each edge of a cube is increased by 50%,then find the percentage increase in its surface area ?
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Surface area of cube = 6a^2
Percent of increase =50%
So, surface area=6*(50%a)^2
=6*(50/100*a)^2
=6*(0.5a)^2
=6a^2(0.25)
Therefore,0.25 can be written as 25/100
That is 25%
So percent of increase is 100%+25%=125%
This answer is % correct answer
Percent of increase =50%
So, surface area=6*(50%a)^2
=6*(50/100*a)^2
=6*(0.5a)^2
=6a^2(0.25)
Therefore,0.25 can be written as 25/100
That is 25%
So percent of increase is 100%+25%=125%
This answer is % correct answer
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