Question

If each edge of a cube is screen by 25 percentage then find the percentage increase in its surface area

Answer 1

Hlw mate

Assume the initial value of edge was xx

So, Initial Surface Area, A1=6x2A1=6x2

The edge increased by 50%, so, the final edge length is, 3x/23x/2

So, final Surface Area, A2=6(3x/2)2=6(9x2/4)=6x2(9/4)=9/4(A1)A2=6(3x/2)2=6(9x2/4)=6x2(9/4)=9/4(A1)

So, Increase in Surface Area, dA=A2−A1=9/4(A1)−A1=A1(9/4−1)=A1(5/4)dA=A2−A1=9/4(A1)−A1=A1(9/4−1)=A1(5/4)

So, the area increased by 5/45/4

Now, percentage increase will be ((5/4)∗100=1255/4)∗100=125%

So, the percentage increase in the Surface Area of the cube will be 125%.

I hope my answer was helpful. If you’ve any questions regarding Mathematics, Physics or Computers, ask me.

Good Day!!!


Hope it helpful