Question

If each Heena shrub occupies a space of 25 cm, find the perimeter of Shyama's field.​

Answer 1

Answer:

Solution

Transcript

Solution:

(a) Perimeter = Sum of all side

= 4 + 2 + 1 + 5

= 12 cm

Perimeter of fig(a) is 12 cm

(b) Perimeter = Sum of all side

= 23 + 35 + 40 + 35

= 133 cm

Perimeter of fig(b) is 133 cm.

(c) Perimeter = Sum of all side

= 15 + 15 + 15 + 15

= 60 cm

Perimeter of fig(c) is 60 cm.

(d) Perimeter = Sum of all sides

= 4 + 4 + 4 + 4 + 4

= 20 cm

Perimeter of fig(d) is 20 cm.

(e) Perimeter = Sum of all sides

= 2.5 + 2.5 + 0.5 + 0.5 + 4 + 4 + 1

= 5 + 1 + 9

= 15 cm

Perimeter of fig(e) is 15 cm.

(f) Perimeter = Sum of all side

= 4 + 1 + 3 + 2 + 3 + 4 + 1 + 3 + 2 + 3 + 4 + 1 + 3 + 2 + 3 + 4 + 1 + 3 + 2 + 3

= 52 cm

Perimeter of fig(f) is 52 cm

Answer 2

Answer:

(a) Perimeter = Sum of all side

= 4 + 2 + 1 + 5

= 12 cm

Perimeter of fig(a) is 12 cm

(b) Perimeter = Sum of all side

= 23 + 35 + 40 + 35

= 133 cm

Perimeter of fig(b) is 133 cm.

(c) Perimeter = Sum of all side

= 15 + 15 + 15 + 15

= 60 cm

Perimeter of fig(c) is 60 cm.

(d) Perimeter = Sum of all sides

= 4 + 4 + 4 + 4 + 4

= 20 cm

Perimeter of fig(d) is 20 cm.

(e) Perimeter = Sum of all sides

= 2.5 + 2.5 + 0.5 + 0.5 + 4 + 4 + 1

= 5 + 1 + 9

= 15 cm

Perimeter of fig(e) is 15 cm.

(f) Perimeter = Sum of all side

= 4 + 1 + 3 + 2 + 3 + 4 + 1 + 3 + 2 + 3 + 4 + 1 + 3 + 2 + 3 + 4 + 1 + 3 + 2 + 3

= 52 cm

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