If each interior angle of a regular polygon is 135 degree then the number of diagonals of the polygon is equal to (1) 54 (2)48(3)20(4)18
Answers
Answered by
90
Hello Dear.
Here is the answer---
Each interior angle of the Regular Polygon = 135°
Using the Formula,
Each Interior angle of the Regular Polygon = [(n - 2) × 180] ÷ n
135° = (n - 2) × 180/n
180n - 360 = 135n
180n - 135n = 360
45n = 360
n = 360/45
n = 8
∴ Number of Sides in the Regular Polygon is 8.
Now, For Calculating the Number of Diagonals in the Polygon,
Using the Formula,
No. of Diagonals = (n - 3)n ÷ 2
No. of Diagonals = (8 - 3)8 ÷ 2
∴ No. of Diagonals = 5 × 4
∴ No. of Diagonals = 20.
Hence, the number of Diagonals in the Octagon is 20.
Hope it helps.
Here is the answer---
Each interior angle of the Regular Polygon = 135°
Using the Formula,
Each Interior angle of the Regular Polygon = [(n - 2) × 180] ÷ n
135° = (n - 2) × 180/n
180n - 360 = 135n
180n - 135n = 360
45n = 360
n = 360/45
n = 8
∴ Number of Sides in the Regular Polygon is 8.
Now, For Calculating the Number of Diagonals in the Polygon,
Using the Formula,
No. of Diagonals = (n - 3)n ÷ 2
No. of Diagonals = (8 - 3)8 ÷ 2
∴ No. of Diagonals = 5 × 4
∴ No. of Diagonals = 20.
Hence, the number of Diagonals in the Octagon is 20.
Hope it helps.
Answered by
43
Sum of the interior angles of a regular
Polygon of " n " sides is (n-2)×180
That is
n × 135 = (n -2)× 180
3n = (n - 2) × 4
3n = 4n - 8
n = 8.
Therefore the given polygon has 8 sides.
The number of diagonals of a polygon of n sides
= n(n-3)/2
= 8× 5/2
= 20
Polygon of " n " sides is (n-2)×180
That is
n × 135 = (n -2)× 180
3n = (n - 2) × 4
3n = 4n - 8
n = 8.
Therefore the given polygon has 8 sides.
The number of diagonals of a polygon of n sides
= n(n-3)/2
= 8× 5/2
= 20
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