Question

if each orbital can hold maximum of 3 electrons the number of elements in second period of the periodic table is?​

Answer 1

Answer:

12

Explanation:

for second period,

3s,3p present

for3s

2l+1=1

for3p

2l+1=3

a/c to q

each orbit can hold a maximum of 3 electrons

so

3s1*3 3p3*3

now

3+9=12