if each side of a rhombus is 15 cm and one of its diagonal is 18 centimetre, find the area of Rhombus
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Answer: 216 cm2
Step-by-step explanation:
Rhombus ABCD, AB= BC= CD= DA = 15 cm diagonal AC = 18 cm & AC & BD intersect at O.
TO FIND: diagonal BD
Since diagonals of a rhombus bisect each other at right angles.
In right triangle AOB
Hypotenuse AB = 15cm , AO = 9 cm
=> BO = √(AB² - AO² )
=> BO = √(15² - 9² )
=> BO = √(24 * 6)
=> BO = √(2² *6² )
=> BO = 12 cm
=> BD= 2BO
=> BD = 2*12
=> BD = 24 cm
Area of rhombus = 1/2 ( product of its
diagonal )
= 1/2 ( 18 × 24)
= 1/2 x 432
= 216 cm2
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