if each side of a triangle is halved , then its perimeter will be decreased by what per cent ?
Answers
Here, ratio of the length of the sides of new triangle to the length of the corresponding sides of original triangle = 1:2
And triangle CDE ~ triangle ABC ( by AAA Similarity criterion)
So, area ( triangleCDE) : area( triangle ABC)
= 1 : 4 ( by area similarity theorem , which states that ratio of the areas of 2 similar triangles is equal to the square of their corresponding sides
So, If area of smaller triangle is x then the area of larger triangle = 4x
Decrease in area 4x -x =3x
So, percentage decrease
= ( decrease in area/ Original area) * 100
= (3x / 4x)*100
= 75%
hope it helps .....
Answer:
75% decrease
Step-by-step explanation:
let the sides of the triangle be x y & z
their semi-perimeter or s = (x+y+z)/2
let the sides of the new triangle be x/2 y/2 & z/2
their semi-perimeter or s' = (x/2+y/2+z/2)/2
=(x+y+z)/2/2
= (x+y=z)/4
s' = s/2
area of the normal triangle or a = √s(s-x)(s-y)(s-z)
area of new triangle or a' = √s/2(s/2-x/2)(s/2-y/2)(s/2-z/2)
= √s/2(s-x)/2(s-y)/2(s-z)/2
=√(s(s-x)(s-y)(s-z))/16
=a√1/16
= a/4
percentage decrease = 100-((new/old) x 100)
= 100-(((a/4)/a) x 100)
=100-(1/4 x 100)
=100-25
= 75%