Question

3- a stone is thrown vertically upwards with a speed of 5m/s. how high does the stone rise before returning back to earth?

given acceleration due to gravity= 100m/s2

Answer 1

Using Newton's law of motion,
$v^{2} - u^{2} =2as$

where v is the final velocity, u is the initial velocity a is the acceleration and s is the distance traveled. (Taking upwards to be the positive direction and final velocity to be 0.)

=> 0 - 5*5 = 2 * (-100) * s
=> s = -25 / -(200)
=> s = 0.125 m

Answer 2

Answer:

Answer ♡

Using Newton's law of motion,

$v^{2} - u^{2} =2as$

• where v is the final velocity, u is the initial velocity a is the acceleration and s is the distance traveled. (Taking upwards to be the positive direction and final velocity to be 0.)

=> 0 - 5*5 = 2 * (-100) * s

=> s = -25 / -(200)

=> s = 0.125 m