Question

MCQ

In a right triangle ABC right angled at B , if P and Q are points on the sides AB and AC respectively , then,

1.AQ2 +CP2 =2(AC2 + PQ2)

2.2(AQ2 + CP2)=AC2 PQ2

3.AQ2 + CP2 = AC2 + PQ2

4.AQ + CP = 1/2(AC + PQ)

plz explain the answer also

Answer 1

hi again....
c is correct
AQ² +CP² = AC²+PQ²
AP² +PQ²+BP²+BC² =AC² +PQ²
AGAIN,AP² +BP² +BC²=AC²
AB²+BC²=AC²

Answer 2

Answer:

3. AQ2 + CP2 = AC2 + PQ2

Step-by-step explanation:

We know that ,

AB2 + BC2 = AC2

(AP2 + BP2) + BC2 = AC2

Adding PQ2 to both sides ,

AP2 + BP2 + BC2 + PQ2 = AC2 + PQ2

(AP2 + PQ2) + (BP2 + BC2) = AC2 + PQ2

AQ2 + CP2 = AC2 + PQ2

Hence Proved.☺