If each side of an equilateral triangle is doubled then find the ratio of the area of the new triangle and the given triangle
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6
Solution :
i ) Let side of an equilateral triangle = a
Area of the triangle = ( √3/4 )a² ---( 1 )
ii ) If side is doubled ,
side of new equilateral triangle = 2a
Area of new triangle = ( √3/4 )× ( 2a )²---( 2 )
iii ) Required ratio = ( 2 )/( 1 )
= [ (√3/4 )×4a² ]/[ (√3/4) a² ]
After cancellation , we get
= 4 : 1
•••••
i ) Let side of an equilateral triangle = a
Area of the triangle = ( √3/4 )a² ---( 1 )
ii ) If side is doubled ,
side of new equilateral triangle = 2a
Area of new triangle = ( √3/4 )× ( 2a )²---( 2 )
iii ) Required ratio = ( 2 )/( 1 )
= [ (√3/4 )×4a² ]/[ (√3/4) a² ]
After cancellation , we get
= 4 : 1
•••••
Answered by
1
area of an equilateral triangle=√3/4*a^2
area of an equilateral triangle whose sides are now doubled=√3/4*(2a)^2
=√3/4*4a^2
=√3*a^2
ratio=√3/4*a^2:√3*a^2
=1/4:1
=1:4
area of an equilateral triangle whose sides are now doubled=√3/4*(2a)^2
=√3/4*4a^2
=√3*a^2
ratio=√3/4*a^2:√3*a^2
=1/4:1
=1:4
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