if each side of rhombus is 10 cm then the square root of sum of square of its diagonals is :
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We know that the diagonals of a rhombus bisect each other at the centre at 900 and we have assumed the length of the diagonals as x and y. Now, the rhombus cuts into 4 right triangles so using Pythagoras theorem we can find the sides of the rhombus and then add the sides of the rhombus and equate it to 4√13cm.
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