If each side of triangle is doubled,what is the ratio of area of new triangle to that of given triangle
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let the each side of the triangle be 'a'
so area will be
A1 = √(3)/2 *a^2. (actually a area of an equilateral triangle)
now if each side is doubled then
A2 = √(3)/2 *(2a)^2
A2 = √(3)/2 *4a^2
now the ratio of new triangle to the original one will be
A2/A1 = [√(3)/2 *4a^2] ÷ [ √(3)/2 *a^2
A2/A1 = 4a^2/a^2
A2/A1 = 4
A2 = 4*A1
hope this helps.
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so area will be
A1 = √(3)/2 *a^2. (actually a area of an equilateral triangle)
now if each side is doubled then
A2 = √(3)/2 *(2a)^2
A2 = √(3)/2 *4a^2
now the ratio of new triangle to the original one will be
A2/A1 = [√(3)/2 *4a^2] ÷ [ √(3)/2 *a^2
A2/A1 = 4a^2/a^2
A2/A1 = 4
A2 = 4*A1
hope this helps.
please mark as brainliest.
and dont forget to follow me.
♡♥♡♥♡♥♡♥♡♥♡♥♡♥♡
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