Question

If earth receives 2 calorie per minute per centimetre square solar energy what are amplitudes of electric and magnetic fields of radiation

Answer 1

The amplitudes of electric and magnetic fields of radiation are 1026,8 vm^-1 and 2.726 A-turn/m^-1

Explanation:

Given that,

| S | = 2 calorie /m - cm^2

As we know,

| S | = | E * H |

= EH Sin 90 = EH                   (since E is ⊥ to H)

Now,

| S |  = (2 * 4.2 * 10^4)/60

= 1400      ...(i)

Then,

E/H = $\sqrt{u_{o}/E_{0} }$

= √(4π * 10^-7)/(8.85 * 10^-12)

= 376.72 ohm   ...(ii)

By taking the product of (i) and (ii), we get

EH * E/H = 1400 * 376.72

E^2 = 5.274 * 10^5

E = 726.2 vm^-1

By putting E in equation (i),

H = 1400/726.2

= 1.928 A-turn/m^1

Now,

The amplitudes of electric and magnetic fields of radiation are:

$E_{0}$ = $E\sqrt{2}$

= 726.2 * $\sqrt{2}$

= 1026.8 vm^-1

$H_{0} = H\sqrt{2}$

= 1.928 *  $\sqrt{2}$

= 2.726 A-turn/m^-1

Learn more: Amplitude

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