Question

If earth shrinks to 50% of its real radius it's mass remaining same,the weight of a body on the earth will be ?

Answer 1

Answer:

no

Explanation:

because if it's mass will decrease it's gravitational force will also decrease due to which the weight of a body on the earth will not the same.

Answer 2

Answer:

increases by 4 times

Explanation:

we know, w=mg

and, g= GM/r^2

where, m=mass of smaller body

M= mass of earth

r=radius of earth

g= accn. due to gravity

Initial weight= GmM/r^2

now, new radius=50%r=r/2

mass remains same

Hence, required wt.=

=mg

=m×M×G/(r/2)^2

=GmM/(r^2/4)

=4GmM/r^2

=4×initial weight