If electric dipole moment of CuSO4(copper sulphate) molecule is 3.2 X 10(-32) Cm{10 raised to the power minus 32} .now find the separation between Cu and SO4 ions.
Answers
Answered by
62
Electric dipole moment is given by
P = ql
Here,
P = 3.2 x 10 raise to power –32 cm
Q = 2e = 2 x 1.6 x 10 raise to power –19 C
= 3.2 x 10 raise to power –19 C
So the separation between Cu and So4 ions
I = p/q
= 3.2 x 10 raise to power -32/ 3.2 x 10 raise to power –19
= 10 raise to power –13 m
Answered by
3
Answer:
Explanation:
Cu^+2
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