Question

If electric field is given by 3i+2j+6k. find electric flux through surface area 20 unit lying in xy plane

Answer 1

Given,
Electric field , E = 3i + 2j + 6k
We have to find electric flux through the surface area 20 sq unit lying in the XY plane . It means Area vector is perpendicular upon XY plane e.g., A = 20k

Now, electric flux = Electric field.Area
= (3i + 2j + 6k).(20k)
= 3 × 0 + 2 × 0 + 6 × 20
= 120 units

Answer 2

Answer:

Magnitude of electric flux is $120\ k$

Explanation:

It is given that,

Electric field, $E=3i+2j+6k$

Surface area, A = 20 unit

Electric flux is defined as the number of electric lines passing through a particular area. Mathematically, it can be written as :

$\phi=B\times A$

Area vector is in x y plane. So, A = 20 k

$\phi=B\times A$

$\phi=(3i+2j+6k)\times 20k$

$\phi=120\ k$

Hence, this is the required solution.