Question

If element with principal quantum number n 4 were not allowed

Answer 1

Answer:

N=1 present K-shell and the number of elements having K shell=2 N=2 present L shell and the number of element having L shell=8 N=3 present N shell and the number of elements having N shell = 18 N=4 present N shell and the number of elements having N shell = 32 Total number = 2+8+18+32=60.

Explanation:

Answer 2

Answer:

correct answer is 2+8+18+32=60

Explanation:

For n=4;l=0,1,2,3.

N=1 present K-shell and the number of elements having K shell =2

N=2 present L shell and the number of element having L shell =8

N=3 present M shell and the number of elements having M shell =18

N=4 present N shell and the number of elements having N shell =32

Total number =2+8+18+32=60

hope this answer is helpful for you Thank you

Ashish Kumar Meher

Kalahandi,odisha