If elements are given then how we can identify their group number and periods ,which they belong to ???
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Answered by
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For finding block-
Electronic configuration - 1s2 2s2 2p6 3s2 3p6 4s2
The last electron enters in the s block , hence the element belongs to the “s” block.
For finding period-
Write the electronic configuration.Highest value of the principal quantum no. will denotes the period no.
(the numerical value written before the block denotes the principal quantum no.)
Eg: atomic no. 16
Electronic configuration- 1s2 2s2 2p6 3s2 3p4
The highest value of principal quantum no.= 3
Hence , the element belongs to
the third period.
For finding group-
Write the electronic configuration.For s block- it is equal to the no. of ele ctrons in the outermost shell.For p block- it is equal to the no. of electrons in the outermost shell + 10.For d block- it is equal to the no. of electrons in the outermost shell + no. of electrons in the penultimate shell.
Eg: atomic no. - 12, 21, 7
Electronic configuration- 1s2 2s2 2p63s2
Last electron enters in the s block .
Hence, group no.= 2
Electronic configuration- 1s2 2s2 2p6 3s2 3p6 3d1 4s2
Last electron enters in the d block( first 4s is filled then 3d).
Hence group no.= 2+1=3
Electronic configuration =1s2 2s2 2p3
Last electron enters in the p block .
Hence , group no.= 5+10=15.
Electronic configuration - 1s2 2s2 2p6 3s2 3p6 4s2
The last electron enters in the s block , hence the element belongs to the “s” block.
For finding period-
Write the electronic configuration.Highest value of the principal quantum no. will denotes the period no.
(the numerical value written before the block denotes the principal quantum no.)
Eg: atomic no. 16
Electronic configuration- 1s2 2s2 2p6 3s2 3p4
The highest value of principal quantum no.= 3
Hence , the element belongs to
the third period.
For finding group-
Write the electronic configuration.For s block- it is equal to the no. of ele ctrons in the outermost shell.For p block- it is equal to the no. of electrons in the outermost shell + 10.For d block- it is equal to the no. of electrons in the outermost shell + no. of electrons in the penultimate shell.
Eg: atomic no. - 12, 21, 7
Electronic configuration- 1s2 2s2 2p63s2
Last electron enters in the s block .
Hence, group no.= 2
Electronic configuration- 1s2 2s2 2p6 3s2 3p6 3d1 4s2
Last electron enters in the d block( first 4s is filled then 3d).
Hence group no.= 2+1=3
Electronic configuration =1s2 2s2 2p3
Last electron enters in the p block .
Hence , group no.= 5+10=15.
Answered by
1
hlw mate ,
____________________
ur answer ,
================⬇️⬇️⬇️⬇️⬇️
hlw, their is a trick to find them my chemistry teacher told me about this ...
TRICK : PERIODS = NUMBER OF SHELL
GROUP NUMBER = VALENCE ELECTRON +10
VALENCE ELECTRON MEANS THE TOTAL NUMBER OF ELECTION IN THE OUTERMOST SHELL
____________________
ur answer ,
================⬇️⬇️⬇️⬇️⬇️
hlw, their is a trick to find them my chemistry teacher told me about this ...
TRICK : PERIODS = NUMBER OF SHELL
GROUP NUMBER = VALENCE ELECTRON +10
VALENCE ELECTRON MEANS THE TOTAL NUMBER OF ELECTION IN THE OUTERMOST SHELL
nameisunknown:
thnk q .....its really helpful
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