Question

If eleven times the complement of an angle is 10 degree greater than three times its supplement, then find the measure of the angle

Answer 1

Answer:

$55^{0}$

Step-by-step explanation:

let angle be x

its complement be 90 - x

its supplement be = 180- x

ATQ , 11 [ 90 - x ] = 3 [ 180 - x ] + 10

990 - 11x = 540 - 3x + 10

990 - 550 = -3x + 11 x

440 = 8 x

440 / 8 = x

$55^{0}$ = x

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