Math, asked by hala8933, 8 months ago

The coach of a cricket team buys 7 bats and 6 balls for Rs.3800.Later ,she buys 5 bats and 5 balls for Rs.1750.Find the cost of each bat and each ball.

Answers

Answered by handsomeram16645
2

question

The coach of a cricket team buys 7 bats and 6 balls for Rs.3800.Later ,she buys 5 bats and 5 balls for Rs.1750.Find the cost of each bat and each ball.

solution

Let cost of each bat = Rs x

Cost of each ball = Rs y

Given that coach of a cricket team buys 7 bats and 6 balls for Rs 3800.

So that 7x + 6y = 3800

6y = 3800 – 7x

Divide by 6 we get

y = (3800 – 7x) /6 … (1)

Given that she buys 3 bats and 5 balls for Rs 1750.so that

3x + 5y = 1750

Plug the value of y

3x + 5 ((3800 – 7x) /6) = 1750

Multiply by 6 we get

18 x + 19000 – 35 x = 10500

-17x =10500 - 19000

-17x = -8500

x = - 8500 / - 17

x = 500

Plug this value in equation first we get

y = ( 3800 – 7 * 500) / 6

y = 300/6

y = 50

Hence cost of each bat = Rs 500 and cost of each balls is Rs 50

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Answered by sourya1794
7

Correct Question :-

The coach of a cricket team buys 7 bats and 6 balls for Rs.3800.Later ,she buys 3 bats and 5 balls for Rs.1750.Find the cost of each bat and each ball.

Given :-

  • The coach of a cricket team buys 7 bats and 6 balls for Rs 3800.Later,

  • She buys 3 bats and 5 balls for Rs 1750.

To find :-

  • The cost of each bat and each ball.

Solution :-

Let the cost of each bat be x

and cost of each ball be y

According to the question,

  • 7x + 6y = 3800 ..........................(i)

  • 3x + 5y = 1750 ...........................(ii)

From equation (i)

7x + 6y = 3800

7x = 3800 -6y

x = 3800 - 6y/7 ............................(iii)

Putting the value of x in eq (ii)

\rm\:3x+5y=1750

\rm\longrightarrow\:3\bigg(\dfrac{3800-6y}{7}\bigg)+5y=1750

\rm\longrightarrow\:\dfrac{11400-18y}{7}+5y=1750

\rm\longrightarrow\:\dfrac{11400-18y+35y}{7}=1750

\rm\longrightarrow\:\dfrac{11400+17y}{7}=1750

\rm\longrightarrow\:11400+17y=1750\times\:7

\rm\longrightarrow\:11400+17y=12250

\rm\longrightarrow\:17y=12250-11400

\rm\longrightarrow\:17y=850

\rm\longrightarrow\:y=\cancel\dfrac{850}{17}

\rm\longrightarrow\:y=50

Putting the value of y in equation (iii)

\rm\:x=\dfrac{3800-6y}{7}

\rm\longrightarrow\:x=\dfrac{3800-6\times\:50}{7}

\rm\longrightarrow\:x=\dfrac{3800-300}{7}

\rm\longrightarrow\:x=\cancel\dfrac{3500}{7}

\rm\longrightarrow\:x=500

Hence,the cost of each bat will be Rs 500 and the cost of each ball will be Rs 50.

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