Question

If emprical formula of a compound if CH2O and molecular mass is 180.

Answer 1

$\text{Empirical formula} = CH_2O\\ \\ \text{molar mass of } CH_2O= \\ 12×1 + 1×2 + 16×1 = 12+2+16 = 30\\ \\ So \ n = \frac{180}{30} = 6\\ \\ \text{Compound is =} (CH_2O)_n = (CH_2O)_6 = C_6H_{12}O_6\\ \\C_6H_{12}O_6 \text{ is glucose}$

Answer 2

C6H12O6 is a Glucose .

《hope this will help you》