if energy required for ionization of 0.2g atom of Na is x kj then amount of energy required to ionize 2.3g of Na atom?
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Answer:
11.5 x kj
Explanation:
0.2 g Na → x
1 g Na → x/0.2 (dividing both sides by 0.2)
2.3 g Na → 2.3 * x/0.2 = 2.3/0.2 x = 11.5 x (multiplying both sides by 2.3)
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