if equation 9x^2+6ax+r=0 had equal roots then find the value of a
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Hi ,
9x² - 6ax + ( a² - b² ) = 0
9x²-3(a + b )x -3( a - b )x + (a² - b²)= 0
3x[3x - (a + b)] -(a - b )[3x - ( a + b )]= 0
[ 3x -( a + b ) ][ 3x - ( a - b ) ] = 0
Therefore ,
3x - ( a+ b ) = 0 or 3x - ( a - b ) = 0
3x= ( a + b ) or 3x = ( a - b )
x = ( a + b ) / 3 or x = ( a - b ) / 3
I hope this helps you.
Read more on Brainly.in - https://brainly.in/question/1496315#readmore
9x² - 6ax + ( a² - b² ) = 0
9x²-3(a + b )x -3( a - b )x + (a² - b²)= 0
3x[3x - (a + b)] -(a - b )[3x - ( a + b )]= 0
[ 3x -( a + b ) ][ 3x - ( a - b ) ] = 0
Therefore ,
3x - ( a+ b ) = 0 or 3x - ( a - b ) = 0
3x= ( a + b ) or 3x = ( a - b )
x = ( a + b ) / 3 or x = ( a - b ) / 3
I hope this helps you.
Read more on Brainly.in - https://brainly.in/question/1496315#readmore
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