Question

If equation x2-kx+4=0 has equal root then the roots of equation x2+kx+a=0 to be equal toto be equal to

Answer 1

Answer:

a=4

Step-by-step explanation:

x2-4x+k=0 is in the form ax2+bx+c=0 where

a=1,b=-4,c=k

roots are equal,discriminant=0

b2-4ac=0

(-4)2-4(1)(k)=0

16-4k=0

4k=16

k=16/4

k=4

Another equation D=0

a=1,b=k,c=a

b2-4ac=0

k2-4(1)(a)=0

where k=4

42-4a=0

16-4a=0

4a=16

a=16/4

a=4