Question

If equilibrium constant of
CH3COOH+H20 ---> CH3COO- +H30+
Is 1.8 x 10-5, equilibrium constant for
CH3COOH + OH- →CH3COO- + H2O is
(A) 1.8 x 10-9. (B) 1.8 x 10
(C) 5.55 x 10°
(D) 5.55 x 1010​

Answer 1

hope it helps u dear.. ❤

Answer 2

The value of equilibrium constant for reverse reaction is $5.55\times 10^4$

Explanation :

The given chemical equation follows:

$CH_3COOH+H_2O\rightarrow CH_3COO^-+H_3O^+$

The equilibrium constant for the above equation is $K_1=1.8\times 10^{-5}$

We need to calculate the equilibrium constant for the reverse equation of above chemical equation, which is:

$CH_3COO^-+H_3O^+\rightarrow CH_3COOH+H_2O$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

The value of equilibrium constant for reverse reaction is:

$K=\frac{1}{K_1}$

$K=\frac{1}{1.8\times 10^{-5}}$

$K=5.55\times 10^4$

Hence, the value of equilibrium constant for reverse reaction is $5.55\times 10^4$

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