Question

if% error in mass is 2 % &% error in velocity is 1% then% error in momentum​

Answer 1

Answer:

3%

Explanation:

momentum = mass * velocity

% error in mass = 2%

% error in velocity = 1%

Therefore,

% error in momentum = %|Δm|/m

+ %|Δv|/v

= (2+1)%

% error in momentum = 3%