If f(1) = 1, f '(1) = 3 , then the derivative of f(f(f(x))) + (f(x)²) at x = 1 is:
(A) 33 (B) 15
(C) 9 (D) 12
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Answer:
→ f(f(f(x))) + (f(x)²) = f ( f ^ 2 + 1 )
Step-by-step explanation:
f ( 1 ) = 1 , f ' ( 1 ) = 3
→ f(f(f(x))) + (f(x)²) at x = 1
f(f(f(x)) = f * ( f * ( f * 1 ) )
= f * ( f * ( f ) )
= f * ( f ^ 2 )
f(f(f(x)) = f ^ 3
(f(x)²) = f ( 1 ^ 2 )
= f ( 1 )
= f
(f(x)²) = f
→ f(f(f(x))) + (f(x)²) = f ^ 3 + f
→ f(f(f(x))) + (f(x)²) = f ( f ^ 2 + 1 )
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