If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?
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19
Answer:
-1280
Step-by-step explanation:
Put n=1
f(2)=-2f(1)
f(2)=-2*160=-320
Put n=2 we get
f(3)=-2f(2)=-2*(-320)=640
Now put n=3 we get
f(4)=-2f(3)=-2*640=-1280
So Hence f(4)=-1280
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