If f(2)=4 and f′(2)=1, then limx→2xf(2)−2f(x)x−2=
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f(2) = 5, f(3) = 2, f(4) = 5, g(2) = 6, g(3) = 2 and g(4) = 0, find (f ... x→0. 4 − (4 − x2) x2(2 +. √. 4 − x2). = lim x→0. 1. 2 +. √. 4 − x2. = 1. 4 . 3. For which ... greater ...
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