Question

if F=(2i^+4j^)N and D=(5i^+2j^)m then work done is:​

Answer 1

Answer :-

• Work done = F · S

i.e. (2i^+4j^) · (5i^+2j^)

⇒ 2 × 5 + 4 × 2

⇒ 10 + 8

⇒ 18

Hence, work done is 18 J

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