if f=2i+j+2k, r=i+j+2k find torque.
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Answer:
torque = k Nm
Explanation:
the formula of torque is ...torque =f×r
=(2i+j+2k)×(i+j+2k)
.:i×i=j×j=k×k=0
and i×j =k..j×k=i..k×i=j so
=2i×(i+j+2k) +j×(i+j+2k)+2k×(i+j+2k)
=(2i×i+2i×j+2i ×k)+(j×i +j×j+j×2k) +(2k×i +2k×j+2k×2k)
=(0+2k+(-2j)) +(-k +0+2i)+(2j+(-2i)+0)
=2k -2j -k +2i +2j -2i
=k Nm
hope it will help
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