if f={(4, 5), (5, 6), (6, -4) }, g={(4, -4), (6, 5), (8, 5) then find f+g, 2f+4g, |f|, √f, f`2
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1
Answer:
f(x)=log(x+
1+x
2
)
f(−x)=log(−x+
1+x
2
)
f(x)+f(−x)=log((x+
1+x
2
)(−x+
1+x
2
))
=log(1+x
2
−x
2
)
=log(1)
=0
Hence, f(x) is odd.
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