Question

If f and g are real function defined by ??=?+7 and ??=3?5. Find the values of the following (i)?? (?і) ?є (?і??є​

Answer 1

Answer:

(f + g + 2) (x) = x² + 2x +1

Step-by-step explanation:

Hi,

Given that

f(x) = 2x - 1 and g(x) = x² , so we have

i. (3f - 2g) (x)

(3f - 2g) (x) = 3 f(x) - 2 g(x)

(3f - 2g) (x) = 3 (2x-1) - 2x²

(3f - 2g) (x) = 6x - 3 - 2x²

(3f - 2g) (x) = - 2x² + 6x - 3

ii. (fg) (x)

(fg) (x) = (2x-1) ( x² )

(fg) (x) = f(x) . g(x)

(fg) (x) = 2x^{3} - x^{2}2x

3

−x

2

iii. (√f/g) (x)

(√f/g) (x) = \sqrt{\frac{2x - 1}{x^{2} } }

x

2

2x−1

iv. (f + g + 2) (x)

(f + g + 2) (x) = f(x) + g(x) + 2

(f + g + 2) (x) = 2x - 1 + x² + 2

(f + g + 2) (x) = x² + 2x +1