Question

If f is a real valued function such that
f(x+y)=f(x)+f(y) and f(1)=5, then the
value of f(100) is:
(1) 500 (2) 200 (3) 300 (4) 400​

Answer 1

Answer:

option 1 is correct

Step-by-step explanation:

because f(1)=5 is given

(x+y)=f(x)+f(y).

f(2)=2f(1)=2×5=10. [ becausef(n)=nf(1)]

f(3)=3f(1)=3×5=15

similarly

f(100)=100×5=500