Question

If f:n->y is a function defined as f(x) = 4x+3 where y={yen:y=4x+3 for some xen} then find f^-1

Answer 1

Step-by-step explanation:

y = 4x +3

y - 3= 4x

$x = \frac{y - 3}{4}$

therefore

$y {}^{ - 1} (x) = \frac{x - 3}{4}$