Question

If f:R → R, :
RR defined by f (x) = 3x - 2, g(x) = x2 +1, then find
(i) (gof-1)(2), (ii) (gof)(x-1).
​

Answer 1

Answer:

f(x)=3x-2,g(x)=x²+1

f(x)=y

3x-2=y

3x=y+2

x=y+2/3

f(y+2/3)=3y+6/3-2

3y+6-6/3=

3y/3=3

x=f(y)-¹

f(y)-¹=x

(gof-¹)(2)=

g((f-¹(2))=

g(3x-2)=

(3x-2)²+1=

9x²+4-12x+1

9x²-12x+5

(gof)(x-1)=

g(f(x-1))=

g(3(x-1)-2)=

g(3x-3-2)=

g(3x-5)=

(3x-5)²+1=

9x²+25-30x+1=

9x²-30x+26

Answer 2

Answer:

Hope it helps..

Step-by-step explanation:

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