Question

If f (t)=4t^2-3t+6,find i) f (0), ii) f (4), iii)f(-5).​

Answer 1

Answer:

Heya user..........❤

Given, f( t) = 4t^2 -3t +6

Hence,

f(0) = 4 ×(0)^2 -3 ×0 +6

= 6

f(4) = 4 × (4)^2 - 3 × 4 +6

=58

f(-5) = 4× (-5)^2 -3 ×-5 +6

=121

Hope it’s helpful....... ☆(❁‿❁)☆