Question

If f (t)=4t^2-3t+6,find i) f (0), ii) f (4), iii)f(-5).4ff​

Answer 1

Answer:

Step-by-step explanation:

4t2-3t+6 is given equation

f(0)=4(0)2-3(0)+6

f(0)=6

f(4)=4(4)2-3(4)+6

f(4)=64-12+6

f(4)=58

f(-5)=4(-5)2-3(-5)+6

f(-5)=100+15+6

f(-5)=121