If f(t) =4t2-3t+6 find f(0) and f(-5)
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f(t)= 4t²-3t+6________(given)
Case-1) Putting f(0) in f(t)= 4t²-3t+6.
= 4(0)²-3(0)+6
= 0-0+6
=6.
Case-2) Putting f(-5) in f(t)= 4t²-3t+6.
=4(-5)²-3(-5)+6
=100+15+6
=121.
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