Question

If f(t)= 4t2-3t+6, find (i) f(0) (ii) f(4) (iii) f(-5)

Answer 1

Answer:

for f(0) substitute on in the equation so we get 4(0)^2-3(0)+6 so we get 6 for f(4) the same we get 58 and f(-5) the same we get 121