Question

if f vector = 5i+2j-4k the find magnitude of vector f​

Answer 1

f=√45

f  = √(5^2+2^2+(-4)^2)

     = √45

Answer 2

The magnitude of $\vec{f}$ is √45

Given :

$\vec{f} = 5 \hat{i} + 2 \hat{j} - 4\hat{k}$

To find :

The magnitude of $\vec{f}$

Solution :

Step 1 of 2 :

Write down the given vector

Here vector is given by

$\vec{f} = 5 \hat{i} + 2 \hat{j} - 4\hat{k}$

Step 2 of 2 :

Find magnitude of $\vec{f}$

The magnitude of $\vec{f}$

$= |5 \hat{i} + 2 \hat{j} - 4\hat{k}|$

$= \sqrt{ {(5)}^{2} + {(2)}^{2} + {( - 4)}^{2} }$

$= \sqrt{25 + 4 + 16}$

$= \sqrt{45}$

Hence magnitude of $\vec{f}$ is √45

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