in an ap the 4th term and 8th term are 13 and 36 respectively then the common difference is...
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4th term=3a+r.....(I)
13=3a+r...
8th term=7a+r......(II)
36=7a+r
now solve eq (I) and (II) by substitution method
by eq (I)
r=13-3a
put value of r in eq (II)
36=7a+(13-3a)
36=7a+13-3a
36-13=4a
23=4a
a=(23/4)
now put value of a in eq (II)
r=13-3(23/4)
r=13-(69/4)
r=(52-69)/4
r=-(17/4)
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